Lotto 649
05-Apr-2007, 12:22 PM
#25
Senior Member
Join Date: Aug 2002
Location: Mississauga
Posts: 13,184
Originally posted by Zyepher
6 matched numbers for the 38 mill
6 matched numbers for the 38 mill
heard it on the news this morning... regardless of what happens over 30 mill = 40% of the pot...
the most you can ever win is 80% cuz the rest is split by other payouts blah blah blah...
05-Apr-2007, 02:10 PM
#27
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Join Date: Jan 2003
Location: on a race track
Posts: 17,846
to win 649 you need 6 of 6 numbers... thats it ... now in this case 2 people had the same number so they split the prize....
remember the 38 million was an estimate and the real prize amount is determined after they know how many ticket they have sold.
remember the 38 million was an estimate and the real prize amount is determined after they know how many ticket they have sold.
05-Apr-2007, 02:16 PM
#28
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Join Date: Jan 2003
Location: on a race track
Posts: 17,846
chance of getting 649 winning numbers is 10,068,347,520 to 1
since a ticket costs a minimum of 2 dollars the break even point when the odds are in your favour is when the pot is at just over $20 billion dollars .... hmmm the pot is never that high....
since a ticket costs a minimum of 2 dollars the break even point when the odds are in your favour is when the pot is at just over $20 billion dollars .... hmmm the pot is never that high....
05-Apr-2007, 02:23 PM
#29
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Join Date: Mar 2004
Posts: 1,730
Originally posted by gatherer
chance of getting 649 winning numbers is 10,068,347,520 to 1
since a ticket costs a minimum of 2 dollars the break even point when the odds are in your favour is when the pot is at just over $20 billion dollars .... hmmm the pot is never that high....
chance of getting 649 winning numbers is 10,068,347,520 to 1
since a ticket costs a minimum of 2 dollars the break even point when the odds are in your favour is when the pot is at just over $20 billion dollars .... hmmm the pot is never that high....
the numbers do not have to be chosen in any particular order
05-Apr-2007, 03:09 PM
#30
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Join Date: Jan 2003
Location: on a race track
Posts: 17,846
Originally posted by ERTW
wrong, the odds are actually 13,983,816 to 1
the numbers do not have to be chosen in any particular order
wrong, the odds are actually 13,983,816 to 1
the numbers do not have to be chosen in any particular order
49*48*47*46*45*44 = the answer I gave .. you are just doing 49 to the power of 6 which is incorrect because as soon as the first number is choosen, a choice of 49, you only have 48 left to choose from.
the math is not hard and I'm pretty sure I'm correct
05-Apr-2007, 03:13 PM
#31
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Join Date: Mar 2004
Posts: 1,730
Originally posted by gatherer
I agree the numbers don't have to be in any particular order .. thats because the machine puts them in order from lowest on the left side to highest on the right side.. you cannot select a number twice on a single line therefore the equation is:
49*48*47*46*45*44 = the answer I gave .. you are just doing 49 to the power of 6 which is incorrect because as soon as the first number is choosen, a choice of 49, you only have 48 left to choose from.
the math is not hard and I'm pretty sure I'm correct
I agree the numbers don't have to be in any particular order .. thats because the machine puts them in order from lowest on the left side to highest on the right side.. you cannot select a number twice on a single line therefore the equation is:
49*48*47*46*45*44 = the answer I gave .. you are just doing 49 to the power of 6 which is incorrect because as soon as the first number is choosen, a choice of 49, you only have 48 left to choose from.
the math is not hard and I'm pretty sure I'm correct
it is simply 49 choose 6
here, i found some websites too:
http://www.joe-ks.com/archives_jan2004/Lotto_Odds.htm
http://lotterybuddy.com/l649odds.htm
http://en.wikipedia.org/wiki/Lotto_6/49
and it is not 49^6, that ends up being 1.3x10^10, which is billions.. the formula is
n choose p =
n!
-----------
p! (n-p)!
